F(x)=x^2+6x-9

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Solution for F(x)=x^2+6x-9 equation:



(F)=F^2+6F-9
We move all terms to the left:
(F)-(F^2+6F-9)=0
We get rid of parentheses
-F^2+F-6F+9=0
We add all the numbers together, and all the variables
-1F^2-5F+9=0
a = -1; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·(-1)·9
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{61}}{2*-1}=\frac{5-\sqrt{61}}{-2} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{61}}{2*-1}=\frac{5+\sqrt{61}}{-2} $

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